Question

Calculate mass of a photon having 3.6 A wavelength

Answer 1

hello mate

use debroglee equation

λ = h / MV

M = h / λV

M --- mass of proton

h --- planck's constant

λ ---  Wave length

V --- Velocity

λ = 3.6 A⁰ = 3.6 × 10⁻¹⁰ m

h = 6.626 × 10 ⁻³⁴ 

V  =  3 × 10⁸ m/s 

∴ M = ( 6.626 × 10 ⁻³⁴ ) / [ ( 3.6 × 10⁻¹⁰ ) × ( 3 × 10⁸)]

       = 6. 135 × 10⁻³³ kg

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Answer 2

Explanation:

We know that,

$\underline{\boxed{\sf m=\dfrac{h}{λ \nu}}}$

We have,

• $\sf λ=3.6 × 10^{-10} \: m$
• $\sf h = 6.626×10^{-34} \: Js$
• $\sf \nu = c = 3×10^{8} \: m/s$

$\sf m = \dfrac{6.626×10^{-34}\: Js }{(3.6×10^{10} \: m)(3×10^8 \: m/s)}$

$\sf m = \bf 6.135×10^{-29} \: kg$