Question

Calculate mass of glucose which contain 7.2×10^26 atoms of oxygen

Answer 1

7.2×10'26 = mass / 12
mass = 7.2×10'26×12

Answer 2

Answer:

35.868kg

Explanation:

C6H12O6=180g

No.of O2 atoms = 7.2×10^26

6×no.of molecules=7.2×10^26

Moles×NA= 7.2*10^26/6

Moles=1.2*10^26/6.022*10^23

Moles=1.2*10^3/6.022

Moles=199.269

Mole=w/mm. (molecular mass)

199.269=w/180

W=199.269*180

W=35,868.482g

W=35.87 Kg