Question

Calculate mass of kclo3 which gives enough o2 on
heating that can completely react with 2.24L
butane gas
measured at NTP
​

Answer 1

Answer:

Explanation:

By poac of o

3 moles kclo3 = 2moles o2

C4h10+o2=4co2+5h2o

Poac of o

4 moles c4h10=moles of co2

10 moles of c4h10 =2 moles h2o

2moles o2 = 2 moles co2 + moles h2o

2moles o2 = 8 moles c4h10 + 5 moles c4h10

2 moles o2 = 13 moles c4h10

2 moles of o2 = 13×2.24

Volume of o2 = 14.56 lt

Moles of kclo3 required = 9.7

Mass = 1188.25 gm