Question

calculate mass of sodium sulphate required to perare its percent solution in 100 gm of water​

Answer 1

Answer:

25g

Explanation:

Let the mass of sodium sulphate required be =xg

The mass of solution =(x+100)g

x g of solute in (x + 100) g of solution

20% =

x+100

x

×100

20x+2000=100x

80x=2000

x=

80

2000

=25 g

Answer 2

Explanation:

Let the mass of sodium sulphate required be =xg

The mass of solution =(x+100)g

x g of solute in (x + 100) g of solution

20% = x/x+100 ×100

20x+2000=100x

80x=2000

x= 2000/80

=25 g