Question

Calculate mass of solute required to prepare 200 ml of M/4 solution of urea.​

Answer 1

Molarity of solution = 1/4 mol/L

Volume of solution = 200ml = 0.2L

no. of moles of solute(urea) = M X V = 0.2/4 = 0.05 mol

Mass of urea = molar mass x moles = 60 x 0.05 = 3g