Calculate maximum height and range if a body of mass 20 kg is projected horizontally with an angle 30 degree, initial velocity of projection is 20 m/s.
Answers
Answered by
2
Answer:
Maximum height = 20m and range = 10√3
Explanation:
given:- mass of body = 20kg
projected horizantal angle = 30°
intial velocity of projection = 20m/s
★ As we know that ,
Maximum height (H) = u²sin²¢/2g
u²sin²¢/2g Range' R' = u²sin2¢/g
- ∴ H = (20)² sin (30°) /2*10
- H = 400sin30°/20
- H = 20 ×sin30°
- H = 20× 1/2 = 10m
- ∴ R = (20)²sin2* (30°)/g
- = 400 sin60° / 10
- = 40 sin60°
- = 40× √3/2 = 20√3m
___________________________
Answered by
0
Answer:
40× √3/2=20√3m....
...........
Similar questions