Question

Calculate molality of 2.5 g of ethanoic acid.in 75g of benzene

Answer 1

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Answer 2

$\bold {\large {\underline {Answer:-}}}$

Molar mass of $\sf\:C_2H_4O_2$

Molar mass : 60 g

Moles of $\sf\:C_2H_4O_2$ = $\dfrac {2.5}{60}$ = 0.0417 mol

Mass of benzene in Kg = 75 × $\:10^{-3}$

$molality \: of \: C_2H_4O_2 \: \: = \: \: \frac{moles \: of \: C_2H_4O_2}{kg.of \: benzene} \\ \\ = \dfrac{0.0417 \times 1000}{75 } \\ \\ =\bf\: 0.556 \: mol \: kg {}^{ - 1}$