Calculate number of atoms of hydrogen present in 5.6 gm of urea.(molar mass of urea=60gm/mole).also calculate number of atom of n, c&o
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As we know no.of moles of urea in 5.6g=5.6÷60=0.093333333.. Now Molecular formula of urea =CH4N2O means 1 mole of urea contains 4 moles of H atoms then 0.093333..moles of urea have no. of atoms=6.022×10^23×0.093333...×4=2.2474×10^23 Similarly atoms of N = 2×6.022×10^23×0.093333=1.12406652×10^23atoms Atoms of C=Atoms of O=6.022×10^23×0.093333=0.5618526×10^23
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