Question

calculate molality of 900 gram ml of water​

Answer 1

HOLA✌️

Solution:

➡️ Density of water = 1gm/mL

=) Volume of 900gram of water = 900ml

=) Moles of water = Given mass/molecular mass

=) 900/18 = 50mol.

=)Molarity of water = 50/900× 1000

=) 55.55M

Hope it helps you

Answer 2

Given:

Density of water = 1g/ml

Mass of water = 900 g

Now:

Volume of water:

$\implies$ $\sf{\frac{Mass \: of \: density}{Density \: of \: water}}$

$\implies$ $\sf{ \frac{900}{1}}$

$\implies$ $\sf{900 \: ml}$

Therefore:

Volume of water = 900 ml

Calculate the moles of water:

Moles of water:

$\implies$ $\sf{\frac{Mass \: of \: water}{Molar \: mass \: of \: water} }$

$\implies$ $\sf{\frac{900}{18}}$

$\implies$ $\sf{ 50 \: moles}$

Calculate the molarity of water:

Molarity of water:

$\implies$ $\sf{ \frac{Moles \: of \: water}{Volume \: of \: water} \times 1000}$

$\implies$ $\sf{ \frac{50}{900} \times 1000}$

$\implies$ $\sf{ 55.5}$

Therefore:

The molarity of 900 g of water is 55.5 M.