Question

Calculate Molar Solubility of AgBr

Answer 1

Answer:The molar solubility of AgBr in pure water is s=7.3×10−7 M

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Answer 2

Explanation:

Compare the molar solubility of AgBr in pure water and in a 0.10 M NaBr solution.

AgBr(s) <====> Ag+(aq) + Br-(aq)

In pure water.

Let 'x' be the [Ag+] and the [Br-] in a saturated solution of AgBr.

Therefore Ksp = [Ag+][Br-] = (x) (x) 4.8 x 10-13 = x2

= 6.9 x 10-7 mol/L.

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