Chemistry, asked by gowthamcongress9, 5 months ago

calculate molarity of solution having 5grams of caco3 in 250 ml solution

Answers

Answered by Anonymous

0

Explanation:

250 ml solution contain 2.5 gm CaCO

3

10 ml solution contain

250

2.5

×10 CaCO

3

=01 gm

number of mole of CaCO

3

=

100

0.1

=0.001

Concentration =

1 litre

0.001

=0.001 mol/litre

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