Calculate mole fraction of hcl in a solution containing 24.8%
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HCl is 24.8% by mass solution..... ie. 24.8 g HCl in 100 g of water.
So, mass of HCl= 24.8g and mass of water = 100-24.8 = 75.2 g.
Molar masses are - HCl = 36.5 g/mol ans
So, mass of HCl= 24.8g and mass of water = 100-24.8 = 75.2 g.
Molar masses are - HCl = 36.5 g/mol ans
Answered by
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HCl is 24.8% by mass solution..... ie. 24.8 g HCl in 100 g of water.
So, mass of HCl= 24.8g and mass of water = 100-24.8 = 75.2 g.
Molar masses are - HCl = 36.5 g/mol ans water - 18 g/mol
Therefore, no. of moles of HCl = ( mass of HCl ) / molar mass of HCl = 24.8/36.5 = 0.68 moles
no. of moles of water = ( mass of water ) / molar mass of water = 75.2 / 18 = 4.18 moles
Hence mole fraction of HCl = (no. of moles of HCl ) / total no.of moles of HCl and water
= (0.68) / (0.68+4.18) = (0.68) / (4.86)
= 0.139
Hence , mole fraction of HCl in the given solution is 0.139.
So, mass of HCl= 24.8g and mass of water = 100-24.8 = 75.2 g.
Molar masses are - HCl = 36.5 g/mol ans water - 18 g/mol
Therefore, no. of moles of HCl = ( mass of HCl ) / molar mass of HCl = 24.8/36.5 = 0.68 moles
no. of moles of water = ( mass of water ) / molar mass of water = 75.2 / 18 = 4.18 moles
Hence mole fraction of HCl = (no. of moles of HCl ) / total no.of moles of HCl and water
= (0.68) / (0.68+4.18) = (0.68) / (4.86)
= 0.139
Hence , mole fraction of HCl in the given solution is 0.139.
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