calculate mole fraction of hcl in solution of hcl containing 24.8% of hcl by mass
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Answered by
76
Hey folk...
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Let us assume total given mass = 100g
Now, we have 24.8g of HCl.
Molecular mass of HCl = 36.45g.
No. of moles = 24.8 / 36.45 = 0.68 moles
Volume of water we have = 100-24.8 = 75.2g
Moles of water we have = 75.2 / 18 = 4.18 moles
MOLE FRACTION OF HCl = (Moles of HCl) / (Total moles) = 0.68 / (0.68+4.18)
= 0.14
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thank you
HOPE IT HELPS..!
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Let us assume total given mass = 100g
Now, we have 24.8g of HCl.
Molecular mass of HCl = 36.45g.
No. of moles = 24.8 / 36.45 = 0.68 moles
Volume of water we have = 100-24.8 = 75.2g
Moles of water we have = 75.2 / 18 = 4.18 moles
MOLE FRACTION OF HCl = (Moles of HCl) / (Total moles) = 0.68 / (0.68+4.18)
= 0.14
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thank you
HOPE IT HELPS..!
Answered by
11
Answer:
moles of HCl=1+35•5=36•5
mole of H2O=18
No of moles of HCl = 24•8÷35•6=0•67
mass of H2O=100-24•8=75•2
moles of water=75•2÷18=4•17
mole fraction of HCl=0•67÷0•67+4•17=0•138
mole fraction of water=4•17÷0•67+4•84=0•3438
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