Calculate molecular formula and empirical formula of compound containing C=54.3%,
H-9%, 0-36.7% molecular mass of compound is 88.
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C=54(approx)
C=54/12=4.5
H=9
0=36%(approx)
O=3
emperical formula=C2H3O
MFM=88
EFM=44(approx)
n=2
Molecular formula=C4H6O2
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