Calculate molecules in 7.50 g of glucose, C6H12O6 ?
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Answer:
180.15588 grams.
Explanation:
the formula mass of a molecule of c6h12o6
i.e. mass of 1 mole of glucose, C6H12O6 = (6 × 12.01 + 12 × 1.01 + 6 × 16.00) g = 180.18 g (using atomic weight data to 2 decimals) 1 mole of carbon atoms weighs 12.01 g and there are 6 moles of C atoms in 1 mole of glucose, so the mass of carbon in 1 mole of glucose = 6 × 12.01 g = 72.06 g
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles C6H12O6, or 180.15588 grams.
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