Question

Calculate moment of inertia and rotational kinetic energy of a thin uniform rod of mass 10 g and length 60 cm when it rotates about a transverse axis through its centre at 90 rpm​

Answer 1

Answer:

The final answer is

1) Moment of Inertia = 9.42

2) Rotational Kinetic Energy = .0532

Explanation:

Given,

We have mass = 10gm.

Length = 60cm

Rotation = 90rpm

We need to find the Moment of Inertia and rotational kinetic energy of the thin rod.

First we need to convert the gm to kgms and length from cm to meters.

f = 90 / 60 = 1.5hz

Length = 60 / 100 = .6m

Mass = 10/1000 = .01

I = M * L* L / 12 = 0.01 * 0.6 * 0.6 / 12 =  0.0003

Angular Speed = 2 * 3.14 * f = 2 * 3.14 * 1.5 = 9.42

Rotational Kinetic Energy = 2 * Angular Speed * Angular Speed * Inertia / 2 = 2 * 9.42 * 9.42 * 0003 = .0532

What is Rotational Kinetic Energy

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