Calculate no:of atoms
a)16moles of Helium (He)
b)16gram of Helium (He)
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solve by avogadro number
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Explanation:
a) I mole oh He contains 6.022 x 10^23 atoms
Since He monatomic gas.
So,16 moles contain 16 x 6.022 x 10^23 atoms
i.e 96.352 x 10^ 23 atoms
b) The molecular weight of He is 4.
So mole of He weighs 4 gram.
Hence 16 gram contain 4 moles of He.
Now 4 x 6.022 x 10^23 = 24.088 x 10^23 atoms
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