calculate no of atoms in 3.2g o f sulphur
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Number of moles in 3.2 grams of Sulphur = 3.2/32 = 0.1 moles
1 mole contains Avogadro number of S atoms
0.1 moles contain →0.1(Avogadro number) of S atoms
→ 0.1(6 x 10²³) S atoms
→ 6 x 10²² Sulphur atoms
Therefore 3.2 grams of sulphur contains 6 x 10²² atoms of sulphur.
1 mole contains Avogadro number of S atoms
0.1 moles contain →0.1(Avogadro number) of S atoms
→ 0.1(6 x 10²³) S atoms
→ 6 x 10²² Sulphur atoms
Therefore 3.2 grams of sulphur contains 6 x 10²² atoms of sulphur.
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