Question

Which has the highest freezing point and why 1M of Glucose or 1M of NaCl

Answer 1

Depression in freezing point = i x Kf x m

In the above formula 'Kfxm' value is same for both glucose and NaCl.
 
The only change is in vant-hoff factor(i)
i for glucose = 1
i for NaCl = 2

Thus the deprssion in freezing point is more for NaCl.

Hence 1M glucose has higher freezing point.

Answer 2

1 M glucose has higher freezing point.

Explanation:

Depression in freezing point  is a colligative property which depend upon the amount of the solute.

$\Delta T_f=i\times k_f\times m$

where,

$T_f$ = change in freezing point

i= vant hoff factor

$k_f$ = freezing point constant

m = molality

1 M glucose: For non electrolytes like glucose, vant hoff factor is 1.

1 M NaCl  : For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i =2 for $NaCl$

As 1 M NaCl produces more ions and thus lowers the freezing point to maximum. Thus 1 M glucose has higher freezing point.

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