Question

calculate no of atoms in 3.2g of sulphur

Answer 1

Given:

3.2g of sulphur

To find:

Number of atoms in 3.2g of sulphur = ?

Calculation:

1 mole of substance contains $6.022\times 10^{23}$.

32g of sulfur = $6.022\times 10^{23}$ atoms

1 g of sulfur = $\frac{6.022\times 10^{23}}{32} atoms$

3.2 g of sulfur = $\frac{6.022\times 10^{23}\times 3.2}{32}$

3.2 g of sulfur = $6.022\times 10^{22}$

Conclusion:

3.2g of sulfur contains $6.022\times 10^{22}$ atoms.

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Answer 2

Answer: 6.022 *10^22

Explanation:

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