Question

calculate the no of atoms in 18g of glucose

Answer 1

hope so this answer help u..

Answer 2

Answer: The number of atoms present in given amount of glucose are $14.4528\times 10^{23}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of glucose = 18 g

Molar mass of glucose = 180 g/mol

Putting values in above equation, we get:

$\text{Moles of glucose}=\frac{18g}{180g/mol}=0.1mol$

The chemical formula for glucose is $C_6H_{12}O_6$.

According to mole concept:

In 1 mole of glucose molecule, $24\times 6.022\times 10^{23}$ number of atoms are present.

So, in 0.1 moles of glucose molecule, $0.1\times 24\times 3\times 6.022\times 10^{23}=14.4528\times 10^{23}$ number of atoms are present.

Hence, the number of atoms present in the given amount of glucose are $14.4528\times 10^{23}$