Question

calculate no of atoms of atoms of each element present in 122.5g of KCLO3

Answer 1

no.of moles = 122.5/122.5 = 1

No.of atoms in KClO₃= 5 x 6.022 x 10²³= 30.110 x 10²³

No.of atoms in K = 6.022 x 10²³

No. of atoms in Cl = 1 x 6.022 x 10²³

No. of atoms in O₃ = 3 x 6.022 x 10²³

                                = 18.066 x 10²³

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Answer 2

Number of Atoms of potassium - 6.022 ×10^23

Number of Atoms of chloride - 6.022×10^23

Number of Atoms of Oxygen - 18.066 ×10^23

GIVEN:

Weight of KClO3 - 122.5 kg

TO FIND:

Number of atoms of each element.

SOLUTION:

We can simply solve the problem as under -

Molar mass of KClO3 = 122.5 grams/moles

Number of moles = given weight / molecular. weight

Number of moles of KClO3 = 122.5/122.5 = 1 mole

we know that,

Number of moles of potassium atoms in KClO3 = 1

Number of moles of Chloride atoms in KClO3 = 1

Number of moles of oxygen atoms in KClO3 = 3.

NOW, We know that

$1mole = 6.022 \times {10}^{23}atoms$

so,

Number of atoms in 1 mole of potassium atom =

$6.022 \times {10}^{23} atoms$

Number of atoms in 1 mole of chlorine atom =

$6.022 \times {10}^{23} atoms$

Number of atoms in 3 moles of Oxygen atoms =

$3 \times 6.022 \times {10}^{23}$

=

$18.066 \times {10}^{23} atoms$

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