Question

Calculate no. Of electrons in11. 2lit of carbon dioxide at normal temperature and pressure

Answer 1

Answer:

6.6253 x $10^{24}$

Explanation:

One mole of any gas occupies a volume 0f 22.4 lit at NTP. Since the given gas has a volume of 11.2 lit , half mole of the gas is present.

A single carbon dioxide atom contains 22 electrons ( since number of electrons in carbon is 6 and there are 8 electrons in each oxygen atom).

1 mole of carbon dioxide contains contains 6.023 x 10²³ atoms

1/2 mole contains 3.0115 x 10²³ atoms.

therefore total number of electrons in 11.2 lit of carbon dioxide is

22 x 3.0115 x 10²³ = 66.253 x 10²³ = 6.6253 x $10^{24}$