Question

Calculate no. Of glucose molecules present in 540 g of glucose

Answer 1

Answer:

$\displaystyle{\implies \ 1.806\times10^{24} \ molecules}$

Explanation:

$\displaystyle{Given \ mass=540g}\\\\\\\displaystyle{Molar \ mass \ of \ glucose \ or \ C_6H_{12}O_6=180g}\\\\\\ \displaystyle{We \ know \ ;}\\\\\\\displaystyle{No. \ of \ moles=\frac{Given \ mass}{Molar \ mass}}\\\\\\\displaystyle{putting \ values}\\\\\\\displaystyle{No. \ of \ moles=\frac{540 \ g}{180 \ g}}\\\\\\\displaystyle{No. \ of \ moles=3 \ moles.}$

$\displaystyle{We \ know \ ;}\\\\\\\displaystyle{One \ mole \ contains \ 6.022\times10^{23} \ molecules}\\\\\\\displaystyle{3 \ moles \ contains \ ;}\\\\\\\displaystyle{\implies \ 3\times6.022\times10^{23} \ molecules}\\\\\\\displaystyle{\implies \ 18.066\times10^{23} \ molecules}\\\\\\\displaystyle{\implies \ 1.806\times10^{24} \ molecules}$

Thus we get answer.

Answer 2

Answer :-

No. of molecules present in glucose = 18.066 × 10^23 .

Explanation :-

Given :-

mass of glucose = W = 540 g

molar mass of glucose = M = 180 g/mol

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To find :-

No. of molecules present in glucose.

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We know that,

No. of moles = Mass/Molar mass

No. of moles of glucose = 540/180

No. of moles of glucose = 3 moles

Now,

No. of molecules = No. of moles × Avagadro's No.

No. of molecules = 3 × 6.022 × 10^23

No. of molecules = 18.066 × 10^23

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∴ No. of molecules present in glucose = 18.066 × 10^23.

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