Question

Calculate no. of ions in 9.5g of magnesium chloride.

Answer 1

Answer:

Explanation:

MgCl₂ mass = 24 + 35.5 × 2

                   = 24 + 71

                   = 95 g

moles = mass given/molar mass

         = 9.5/95

          = 0.1 mol

no of ion = moles × Na (avogadro's no. )

               = 0.1 × 6.022 × 10²³

               = 6.022 × 10²²

Answer 2

Explanation:

No.of ions = (Given mass/Molecular Mass ) × Avogadro number

Molecular mass of Magnesium Chloride = 95g

Avogadro number = 6.022 × 10²³

No. of ions = $\frac{9.5}{95} \times 6.022 \times {10}^{23}$

$= \frac{1}{10} \times 6.022 \times {10}^{23}$

$= 6.022 \times {10}^{22}$