calculate no of molecules in a drop of water weighting 0.05g
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Answered by
2
Hey mate!
Here's your answer!!
Molecular mass of water = 18 g
No. of moles in 0.05 g of water = 0.05/18
= 2.78 x 10^-3 mol
One mole = 6.0^23 x 10^23 molecules
Therefore,
2.78 x 10^-3 mol of water contain = 2.78 x 10^-3
6.0^23 x 10^23 molecules
= 1.67 x 10^21 molecules
✌ ✌
Here's your answer!!
Molecular mass of water = 18 g
No. of moles in 0.05 g of water = 0.05/18
= 2.78 x 10^-3 mol
One mole = 6.0^23 x 10^23 molecules
Therefore,
2.78 x 10^-3 mol of water contain = 2.78 x 10^-3
6.0^23 x 10^23 molecules
= 1.67 x 10^21 molecules
✌ ✌
Answered by
1
no.of molecules in one drop. of H2O molecule = avagadro no. × no of moles
=6.022×10^23×.003
=0.018066×10²³
=1.8×10²¹
=6.022×10^23×.003
=0.018066×10²³
=1.8×10²¹
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