Question

Calculate no. Of molecules in drop of water weighing 0.036g

Answer 1

$\huge\underline\green{\sf Answer}$

$\large{\boxed{\sf No.\:Of\:Molecules=12 \times {10}^{20}}}$

$\huge\underline\green{\sf Solution}$

$\large{\sf 1\:Mole=18g = 6.023 \times {10}^{23}}$

$\large{\sf 1g={\frac{6.034 \times {10}^{23}}{18}}}$

So,

$\large{\sf {\frac{36}{1000}}={\frac{6.023 \times {10}^{23}}{18}}{\frac{36}{1000}}}$

$\large\implies{\sf {\frac{6.023 \times {10}^{20} \times 36}{18}}}$

$\large{\boxed{\sf No.\:Of\:Molecule = 12 \times {10}^{20}}}$

Answer 2

Answer:

$\huge\mathfrak\pink{Thanks}$