Question

Cos theta=2/3. Then find the value of 2sec 2 theta

Answer 1

Answer:

$2sec^{2}\theta = \frac{9}{2}$

Step-by-step explanation:

$cos\theta = \frac{2}{3}$

$sec\theta\\= \frac{1}{cos\theta}\\=\frac{3}{2}$

$\implies 2sec^{2}\theta\\=2\times \left(\frac{3}{2}\right)^{2}\\=2\times \frac{9}{4}\\=\frac{9}{2}$

Therefore,

$2sec^{2}\theta = \frac{9}{2}$

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Answer 2

Answer:

cos¤=2/3

sec¤=3/2

2sec^2¤=2(3/2)^2=2(9/4)=9/2