Calculate no.of molecules of O2 gas that occupies a volume of 224 ml at 273 K and 3 atm pressure.
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N = pv ÷ RT
.n = 3 × 0.224liter ÷ 0.0821 × 273
n= 0.672 ÷ 22.4
n = 0.0299mole
Number of molecules = n × Na
= 0.0299 × 6.02× 10^23
= 0.1804 × 10^23
= 1.804 × 10^22
Hope it helps you ... Mark as brainlist plz PlzZ plzz
.n = 3 × 0.224liter ÷ 0.0821 × 273
n= 0.672 ÷ 22.4
n = 0.0299mole
Number of molecules = n × Na
= 0.0299 × 6.02× 10^23
= 0.1804 × 10^23
= 1.804 × 10^22
Hope it helps you ... Mark as brainlist plz PlzZ plzz
tawaseem:
Ok will mark as brainliest.Let someone else answer.
Thanks for helping me out with the answer.May God bless you.
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