Question

Calculate normality and molarity of 4.9 (w/v) h2so4 solution density of sol is 1.2 gm per ml

Answer 1

Answer:

• Molarity=0.5M
• Normality=1N

Explanation:

4.9%w/v means 4.9g of h2so4 is present in 100ml solution

so V=100ml

d=1.2g/ml

m=120g

W/V =w.t of solute/volume of solution×100

=x/100×100=4.9=mass of solute=4.9g

no of moles of h2so4 =mass/molar mass

=4.9/98=0.05mol

volume of solution=100ml=100/1000L

molarity=no of moles/vol of solution in L

molarity=0.05/100/1000=0.05×1000/100=0.5M

when molarity is found

for acids normality=

NORMALITY=MOLARITY×BASICITY

N=M×n

basicity=no of ionizable hydrogen ion present in

1 molecule of acid in sulfuric acid there is 2 H+ ions so basicity =2

now

N=M×n==>N=0.5×2=1N