Question

Calculate normality molarity and molality of his sample a sample of sulphuric acid content 98% h2 s o4 by mass of density is 1. 0 2 gram/ml.

Answer 1

Given : Molarity of H2SO4 = 18M

 

              As,  Molarity = volume of solutionno. of moles of solute

i.e., 18moles of sulphuric acid is present per litre of solution.

             Density=1.8g/mL               {given}

Thus , mass of one litre of this solution ,

 Density = volumemass

mass = density×volume   

mass = 1.8×1000

mass = 1800g

Thus , mass of 1litre 18M H2SO4 solution is 1800g or 1.8kg.

Now, mass of solution = mass of solute + mass of solvent 

          mass of solution = no. of moles of solute X molar mass of solute + mass of solvent

         1800 = 18×98 + mass of solvent 

          mass of solvent = (1800−1764)g

mass of solvent is equal to 36 g

Answer 2

Answer:

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