Question

in the given figure, if AB=AC and angle ACD =115°,then find angle BAC​

Answer 1

Answer:

50°

Step-by-step explanation:

 Adjacent ∠ to  115° + 115° = 180°

⇒ ∠ ACB  + 115° = 180°

⇒ ∠ACB = 180° - 115°

⇒ ∠ACB = 65°

   As AC = AB  ⇒ ∠ACB = ∠ABC

      ⇒ ∠ABC = 65°

In any triangle sum of all angles is 180°

⇒ ∠ABC + ∠ACB + ∠BAC = 180°

⇒ 65° + 65° + ∠BAC = 180°

⇒ 130° + ∠BAC = 180°

⇒ ∠BAC = 180° - 130°

⇒ ∠BAC = 50°

Answer 2

Step-by-step explanation:

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