Question

Calculate normality of 0.321gm of sodium carbonate when it mixed with 250ml of solution

Answer 1

molar mass of Na2CO3 is 2 x 23 + 12 + 48 =>  106 grams per mole.

So, 0.321 grams of Na2CO3 is 0.321/106 =>0.00303 moles (approx.)

Volume of solution = 250 mL => 0.25 liters

So, molarity of solution = (moles of solute )/(liters of solution)

=>0.00303 /0.25

=>0.00303 x 100/25

=>0.00303 x 4

=> 0.01212 M

When Na2CO3 dissociates completely, 2 Na+ ions are formed per molecule.

N-Factor for a salt is equal to the number of H+ ions that can completely replace the cation, here, N-Factor will be 2 x +1 => 2

So, N-factor for Na2CO3 is 2 .

Normality = molarity x N-factor

=> 0.01212 x 2 =>0.02424 N

So, the normality of the solution is 0.02424 N .