Question

Calculate number of aluminium atom present in 00.051g of aluminium oxide. (Al=27u, O=16u)

Answer 1

Answer:

6.022*10^20

Explanation:

no. of Al atoms in Al2O3

=no of total atoms of Al*no.of molecules

=2*moles*NA

=2*given weight/molecular weight*NA

=2*0.051/2(27)+3(16)*6.022*10²³

=2*0.051/102*6.022*10²³

=2/102*0.051*6.022*10²³

=1/51*0.051*6.022*10²³

=0.051/51*6.022*10²³

=1/1000*6.022*10²³

=6.022*10²³/1000

=6.022*10²³/10³

=6.022*10²°

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