Question

calculate number of + and - ions from 95 gram of MgCl2.



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Answer 1

Answer:

95 g of $MgCl_{2}$ contains $6.022 * 10^{23}$ + ions and $12.044 *10^{23}$ - ions.

Explanation:

Given mass = 95 g

Molar mass of $MgCl_{2}$ = (1 * 24.3) + (2 * 35.5 )

                                   = 95.2 g/mol ≈ 95 g/mol

Number of moles = given mass ÷ molar mass

                             = $\frac{95}{95}$

                            = 1 mole

$MgCl_{2}$ → $Mg^{+2} + 2Cl^{-1}$

1 mole contains $6.022 * 10^{23}$ particles

1 mole of $MgCl_{2}$ contains $6.022 * 10^{23}$ $Mg^{+2}$ ions

1 mole of $MgCl_{2}$ contains $2*6.022 * 10^{23}$ $Cl^{-1}$ ions

                                         = $12.044 *10^{23}$ $Cl^{-1}$ ions

Answer 2

kindly refer the attachment...