If a,b #1, ab > 0,a #b and logba =logab, then ab =?
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Step-by-step explanation
Given, log
b
a=log a
b
⇒
logb
loga
=
loga
logb
⇒(loga) 2
=(logb) 2
⇒(loga) 2
(logb) 2
=0
⇒(loga−logb)(loga+logb)=0
⇒loga−logb=0 OR loga+logb=0
⇒log ab
=0 OR logab=0
⇒log ba
=log1 OR logab=log1
ab
=1 OR ab=1
⇒a=b OR ab=1
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but given a
=b
∴ab=1
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