Question

Calculate number of atoms in 11.2 l of so2 gas at stp

Answer 1

Given Volume of Sulfur Dioxide Gas = 11.2 Litres

we knwo that:-

$Moles=\dfrac{volume\:given}{22.4}$

Hence:-

Moles of SO2 given will be :-

$=\dfrac{11.2}{22.4}\\ \\ \\=0.5\:Moles$

$\rule{200}{2}$

Now:-

we know that :-

$1\:Mole=N_A\:molecules$

Thus:-

Total molecules present in 11.2L SO2 will be :-

$=0.5*N_A$

where:-

$N_A=6.022*10^{23}$

$\rule{200}{2}$

1 molecule of SO2 has total 3 atoms.

1 atom of S and 2 atoms of O

$\rule{200}{2}$

Total number of atoms given :-

$=0.5*N_A*3\\ \\ \\=1.5N_A\:Atoms$

where:-

$N_A=6.022*10^{23}$

$\rule{200}{2}$