Question

Calculate Number Of Atoms Of Hydrogen Present In 5.6 g of urea . Also calculate number of atoms of N,C,O

Answer 1

HELLO MATE

Answer:

(No. of atoms of H = 2.24×10^23 , N=1.124×10^23 and C=0.562×10^23 , O=0.562×10^23)

Explanation:

Mass of urea = 5.6g

Molar mass of area (NH2)2= 60g/mol

No. of moles of urea = mass of urea / molar mass

=5.6/60

=0.0933moles

No.of molecules of NH3 in 5.6g of area = 0.0933×6.022×10^23

=0.562×10^23 molecules

1 mole of urea contains 2N atoms, 4-H atoms ,1C atom and 1 O atom

5.6g of urea contains

a) No.of N-atoms =2×0.562×10^23

=1.124×10^23 atoms

b) No.of H-atom =4×0.562×10^23

=2.24×10^23

c) No.of C-atom =1×0.562×10^23

= 0.562×10^23

d) No.of O-atom =1×0.562×10^23

= 0.562×10^23

hope this help you buddy .

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