calculate number of electron present in 9.5g of po4'3-
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so u can find this formula...
electron==mol×6.022×10^23×number of electron in po4-3
electron==mol×6.022×10^23×number of electron in po4-3
ralph1:
it's really helpful for me thanks a loy
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Answer : The number of electrons in 9.5 g of is electrons.
Solution : Given,
Mass of = 9.5 g
Molar mass of = 95 g/mole
First we have to calculate the moles of .
Moles of =
1 mole of has molecule of
0.1 mole of has molecule of
Now we have to calculate the number of electrons in .
The number of electrons present in 1 molecule of is,
= (5) + 4(8) + 3 = 40 electrons
Number of electrons present in 1 molecule of = 40 electrons
Number of electrons present in molecule of = electrons
Therefore, the number of electrons in 9.5 g of is electrons.
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