calculate number of H-atoms in 9g of NH4^+
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NH4
M wt = 18
9 gm = 9/18 = 0.5 moles
1 mole of NH4 contains 4N atoms of H
0.5 moles contains 2N atoms of H
= 12.05 x 10^23 atoms
= 1.205 x 10^24 atoms of H
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