Calculate number of molecules present in 11.2 litre of oxygen at SPT.
Answers
Answered by
119
1 mole of any substance occupies 22.4 litre of volume at STP
22.4 l = 1 mole = avagadro's number of particles
11.2 l of oxygen
= 1/2 Mole of oxygen
= N•/2 number of oxygen molecules
= 6.022 * 10^22
= 3.011 * 10^22 molecules
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22.4 l = 1 mole = avagadro's number of particles
11.2 l of oxygen
= 1/2 Mole of oxygen
= N•/2 number of oxygen molecules
= 6.022 * 10^22
= 3.011 * 10^22 molecules
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Answered by
60
at 1 atm and at 0°c that is at 273kelvins the volume of a gas is 22.4litres.
so volume is inversely proportional to temperature. then 1mole = contains 22.4 litres in STP. Then the no. of moles in 11.2 litres=22.4/11.2=2moles.
so no. of molecules in 2moles =6.022×10²³×2=12.044×10²³.
so volume is inversely proportional to temperature. then 1mole = contains 22.4 litres in STP. Then the no. of moles in 11.2 litres=22.4/11.2=2moles.
so no. of molecules in 2moles =6.022×10²³×2=12.044×10²³.
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