Calculate number of moles and molecules of ammonia present in 5.6dm^3 of its volume
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the molecular mass of NH3 is (1×14)+(1×3)
=17
then in 22.4 litre NH3 the number of molecule is 6.022×10^23
therefore,the number of molecule in 5.6 is, 6.022×10^23/22.4×5.6
=1.5055×10^23
=17
then in 22.4 litre NH3 the number of molecule is 6.022×10^23
therefore,the number of molecule in 5.6 is, 6.022×10^23/22.4×5.6
=1.5055×10^23
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