Question

Calculate number of moles of 112 cc of O2 at STP

Answer 1

Answer:

32 gm of oxygen weighs 22.4 l at stp.

Therefore,112 l of of oxygen weighs =22.4/32*112

=78.4 l (since 1 cu.cm=1 l)

Explanation:

Hope it helps.

Answer 2

Answer:

0.005 moles

Explanation:

We know that at STP,

$\underline{\boxed{ \sf Moles = \dfrac{Volume\:(in\: litre)}{22.4}}}$

$\sf Volume \: of \: O_2 = 112 \: cc = 112 \: cm³ = 0.112 \: litres$

$\sf Number \: of \: moles = \dfrac{0.112}{22.4} = 0.005 \: moles$

Hence the number of moles of 112 cc of oxygen molecule at STP is 0.005 moles.