Calculate number of protons, Neutron, electrons ans also electronic configuration of 23NA11
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Write the number of protons , neutrons and electronic configuration of ^39 K19 , ^31P15 . Also state their position in periodic table .
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Atomic number = Number of protons Hence , number of protons in K atoms = 19 Number of neutrons = Mass number - Atomic number Hence , number of neutrons in K atom = 39 - 19 = 20 Number of electrons = Number of protons Hence , the number of electrons = 19 And electronic configuration of K atom = 2 , 8 , 8 , 1 Since K atom has 4 shells , hence it belongs to fourth period. With one valence electron , it belongs to group 1 Number of protons in P atom = 15 Number of neutrons in P atom = 31 - 15 = 16 Number of electrons in P atom = 15 And electronic configuration of P atom = 2 , 8 , 5 Since it has three shells , it belong to period 3 and with 5 valence electrons Phosphorous is found in five plus ten that is 15^th group.
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