Question

calculate numerical aperture acceptance angle and critical angle of a fiber having core refractive index=1.50and cladding refractive index =1.45
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Answer 1

Answer:

Critical angle is calculated above. Sorry, I can't help you with acceptance and numerical angle as they are beyond my syllabus.

Answer 2

Answer : Critical angle θc = 75° ,. Numerical Aperture ( NA) = 0.387 Acceptance angle (θa) = 22.76° Step-by-step Explanation : Given : Core Refractive index ( μ1 ) = 1.50 Cladding Refractive index ( μ2 ) = 1.45 To find : Numerical aperture = ? Acceptance angle = ? Critical angle = ? We know that , Critical angle θc is given by, Sin(θc) = μ2 / μ1 θc = Sin−1 ( 1.45 / 1.50 ) = Sin−1 ( 0.966 ) = 75° And , Numerical aperture ( NA) = ( μ1² - μ2² ) ½ Substituting the given value in above formula we get, NA = [ ( 1.50 )² - ( 1.45 ) ² ] ½ = [ 2.25 - 2.10 ] ½ = ( 0.15 )½ = 0.387 Also , Acceptance angle (θa) = Sin−1 ( NA ) Substituting the value in above formula we get , Acceptance angle = Sin−1 (0.387) = 22.76° Hence the Critical angle θc = 75° ,. Numerical Aperture ( NA) = 0.387 Acceptance angle (θa) = 22.76°