Question

Calculate % of N in NH4H2PO4

Answer 1

SYMBOL      ELEMENT          ATOMIC WEIGHT      ATOMS     MASS PERCENT

N                  NITROGEN           14.0067                        1                   12.1770%

H                 HYDROGEN         1.00794                         6                  5.2576%

P                PHOSPHORUS     30.973762                     1                  26.9277%

O                  OXYGEN             159994                           4                55.6377%

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Answer 2

Answer:

The % of N in NH₄H₂PO₄ is 12.17%

Explanation:

For calculating the percentage of Nitrogen we need to calculate the mass of the whole compound first.

Molar mass of NH₄H₂PO₄ = sum of molar masses individual elements

Mass of nitrogen(14g)+ mass of hydrogen(1g) × 6+ mass of Phosphorus(31g)+mass of oxygen (16g) × 4 = 115  g

Percentage of nitrogen

  molar mass of Nitrogen÷ molar mass of NH₄H₂PO₄

   14÷115 = 0.1217 g

% Of N = 0.1217 × 100 = 12.17%