Question

Calculate osmotic pressure of the solution of 6.5 gram of glucose dissolved in 200 ml of water at 300 kelvin

Answer 1

OP =
Wa×R×T

------------

Ma×V

vol. of solution (v) = 200 ml

molecular mass of glucose(Ma) = 180

wt. of solute (Wa)= 6.5 gm

value of temp. = 300k

R = 0.0082

now,

6.5×0.0082×300

------------------------

180×200

you can calculate this and find the value now

Answer 2

The formula of osmotic pressure is pi= CRT

Here ,pi is osmotic pressure

C is concentration of solution

R is gas constant

T is Temperature in Kelvin

Molecular weight of glucose is 180

Osmotic pressure =6.5×0.0821×300/180×0.2

=160.095/36=4.44 atm