Math, asked by Ajaypangi743, 1 year ago

By mixing two qualities of pulses in the ratio 2: 3 and selling the mixture at the rate of rs 22 per kilogram, a shopkeeper makes a profit of 10 %. If the cost of the smaller quantity be rs 14 per kg, the cost per kg of the larger quantity is:

Answers

Answered by insaneabhi
8

Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).

Sell price of 5 kg = Rs. (22x5) = Rs. 110.

[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10

[82-3x/28 + 3x]= 1 / 10

820 - 30x = 28 +3x

33x = 792

x = 24

Answered by Pitymys
2

Answer:

Cost Price of Larger Quantity of pulse is Rs. 24 per kg.

Step-by-step explanation:

Given:

Selling Price of mixture of pulses = Rs. 22  per kg

Ratio in which two qualities of pulses are mixed = 2 : 3

Cost price of the smaller Quantity = Rs. 14 per kg

Percentage of Profit on mixture = 10%

To find: Cost Price of Larger Quantity.

Let the Quantities of the type of pulses are 2x and 3x

So. Total Quantity = 2x + 3x = 5x

Total Selling Price of mixture = 5x × 22 = Rs. 110x

let the cost price of larger Quantity pulse = Rs. y per kg

Total Cost Price = 2x × 14 + 3x × y = 28x + 3xy

According tot the Question,

10=\frac{110x-(28x+3xy)}{28x+3xy}\times100

10=\frac{110-28-3y}{28+3y}\times100

\frac{1}{10}=\frac{82-3y}{28+3y}

28+3y=10(82-3y)

28 + 3y = 820 - 30 y

33y = 820 - 28

33y = 792

y = 24

Therefore, Cost Price of Larger Quantity of pulse is Rs. 24 per kg.

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