Question

Calculate ostimatic pressure at 273k of 5% solution of urea ( molar mass= 60) r= 0.0821​

Answer 1

Answer:

∴ π=nVRT=w2M2×1VRT=w2RTM2V=(5g)(0.08211 L atm K-1mol-1)(273K)(60 g mol-1)(0.1 L)=18.68 atm.

Answer 2

Explanation:

*If three coins are tossed simultaneously, than the probability of getting at least two heads, is ……………*

1️⃣ 1/4

2️⃣ 3/8

3️⃣ 1/2

4️⃣ 1/8