Question

calculate oxidation number of Cl given the following (a) HCL (b) Cl2 (c) HCLO (d) HCLO2 (e) HCLO3 (f) HCLO4​

Answer 1

Answer:

1. -1
2. 0
3. +1
4. +3
5. +5
6. +7

Step-by-step explanation:

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Answer 2

Answer:

(a) -1

(b) 0

(c) +1

(d) +3

(e) +5

(f) +7

Step-by-step explanation:

(a) HCl

   The general oxidation number of Hydrogen is (+1)

   Let the oxidation number of Cl be x

   ∴ (+1) + x = 0

      x + 1 = 0

      x = -1

(b) Cl2

    The oxidation number of any molecule made up of same element is 0

   ∴ x = 0

(c) HClO

   The general oxidation number of Hydrogen is (+1)

   And, the general oxidation number of Oxygen is (-2)

   Let the oxidation number of Cl be x,

   ⇒ (+1) + (x) + (-2) = 0

   ⇒ x - 1 = 0

   ⇒ x = +1

(d) $HClO_{2}$

   The general oxidation number of Hydrogen is (+1)

   And, the general oxidation number of Oxygen is (-2)

   Let the oxidation number of Cl be x,

 ⇒ (+1) + (x) +2(-2) = 0

 ⇒ 1 + x -4 = 0

 ⇒ x - 3 = 0

⇒ x = +3

(e) $HClO_{3}$

    The general oxidation number of Hydrogen is (+1)

   And, the general oxidation number of Oxygen is (-2)

   Let the oxidation number of Cl be x,

  ⇒ (+1) + (x) + 3(-2) = 0

 ⇒ 1 + x - 6 = 0

 ⇒ x - 5 = 0

 ⇒ x = +5

(f) $HClO_{4}$

    The general oxidation number of Hydrogen is (+1)

   And, the general oxidation number of Oxygen is (-2)

   Let the oxidation number of Cl be x,

  ⇒ (+1) + (x) + 4(-2) = 0

  ⇒ 1 + x - 8 = 0

  ⇒ x - 7 = 0

  ⇒ x = +7